A card is a “Legal Offspring” of two other cards (a buck and doe) if it is one that could be produced from this mating, given what is known about the genotype.
Legal Mating: Black x Lynx => Amber
The genotype for Amber is: A- bb C- D-
It is a Chocolate Agouti. In order for this to be a legal offspring, the following must be true:
- ONE parent must have the Agouti allele (A)
- BOTH parents must have the Chocolate Allele (b)
- ONE parent must have the full Color allele (C)
- ONE parent must have the Dense allele (D)
If this were a real mating, we could also fill in a few additional alleles on the offspring because of what we know about the parents. Since one parent was a Self (‘aa’) we know for sure that the second allele on the A-locus HAS to be ‘a’. Also, since one parent was Dilute (‘dd’) we also know that the second allele on the D-locus HAS to be ‘d’.
Later on, if we were to use this Amber in a mating, we would be able to predict the colors of the offspring with more accuracy.
Legal Mating: Black X Lynx => Lynx
The genotype for Lynx is: A- bb C- dd
It is a Lilac Agouti. In order for this to be a legal offspring, the following must be true:
- ONE parent must have the Agouti allele (A)
- BOTH parents must have the Chocolate Allele ‘b)
- ONE parent must have the full Color allele (C)
- BOTH parents must have the Dilute allele (d)
If this were a real mating, we could also fill in a one additional alleles on the offspring because of what we know about the parents. Since one parent was a Self (‘aa’) we know for sure that the second allele on the A-locus HAS to be ‘a’.
Later on, if we were to use this Lynx in a mating, we would be able to predict the colors of the offspring with more accuracy.
Legal Mating: Black X Lynx => REW
The genotype for Albino is: — — cc —
It is a Red-Eyed White. In order for this to be a legal offspring, the ONLY thing that must be true is:
BOTH parents must carry the albino allele (c)
If this were a real mating, we could also fill in a few additional alleles because of what we know about the parents. Since one parent was a Self (‘aa’) we know for sure that one allele on the A-locus HAS to be ‘a’. We also know that one of the alleles on the B-locus HAS to be ‘b’. Also, since one parent was Dilute (‘dd’) we also know that one allele on the D-locus HAS to be ‘d’.
So in fact, the known genotype of this offspring would have to be:
-a -b cc -d
It is often written with the unknown (‘-‘) in the first position here because we can’t be sure that the recessive allele is not paired up with one that is dominant to it.
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